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Posted 2015, Aug 16 09:39
In the conversione using deviation exercise, the deviation table represents at 300º Deviation is 0.0 and at 330º deviation is 1.5E, The Compass bearing is 310º, so imho the Deviation should be 0.5E as in between 0.0 and 1.5, in the exercise though the deviation is marked as 2.0E. I don't understand why? Thanks,
Posted 2015, Aug 24 21:33
Hello, I didn't understand how to decide if a given day is neaps or spring tide, could you please explain me more? Thanks, Giulio
Posted 2015, Oct 30 13:15
You are sailing along on heading 50° "psc" (54° Mag)... PSC stands for Per Ships Compass
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Posted 2015, Dec 04 17:00
Why is deviation the same in all headings for the example question. It appears that from the table given above that the deviation should be different, unless they are unrelated?
Posted 2015, Dec 05 20:19
Grant, how accurate are the answers expected to be? I have double checked my answer three times and have not come up with a reason why Lat 46°14'.74N Long 005°50'.20W is the answer and not 46deg14'.85N 5deg51'.00W. Even assuming that the variation number I used was not 7.2deg W, the transit line does not pass through the correct lat/long answer given by the self grading function. In checking this, I show that the lat/long given (Lat 46°14'.74N Long 005°50'.20W) shows a 358(M) bearing to the Bayview Hotel rather than 000 (M). Perhaps I am splitting hairs and this difference is negligible for the purposes of final exam grading? Thoughts? Thanks, Ryan
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Posted 2015, Dec 11 05:19
What curve for Namely harbor should be used in this example, Spring or Neaps? I chose Neaps, however, from the answer bank, this seems to be incorrect and unsure why Spring would be chosen over Neaps.
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Posted 2016, Jan 21 22:49
I've very confused in this section! Why is a curve used at the end of the vector line and not a straight line? How is the length of the vector line determined? Do I use the time/speed formula, determine distance over one hour and use latitude scale on left side of chart? I get the DR course line and the COG line but can't grasp the vector information and where to place it.
Posted 2016, Feb 20 16:02
Hi Grant Regarding the example below, to clarify my understanding, won't more of the rock will be visible at 1030 at low tide, not below the surface? " This above means that in Eastport on the 31th August at 1030 am, the depth of the water will be 2.6 feet below the chart datum depth at any point. e.g. if the harbor reads 7.0 feet deep at a certain point, then the real depth at 1030 will be 7.0 - 2.6 = 4.4m. Or if the chart shows a rock at 2 ft above the datum, at 1030 it will be below the surface. For a 5 ft draft and at 4.4 ft real depth, this could be a grounding situation, even though the chart says 7 ft.
Posted 2016, Apr 28 23:31
When teaching the basic navigation skills for U.S. Sail & Power Squadron the memory reminder for calculating Speed, Time or Distance is "Sixty D Street". That is 60*Distance = Speed * Time. Perhaps this will help NauticEd Students as well.
Posted 2016, May 01 23:07
There is an annual yacht race, CYC, from San Diego to Mission Bay. The fleet rafts up in Mariner's Basin overnight. A couple of late arrivals, cruising class, tied up on one end assuming there was plenty of water under their keel. Late that night masts and rigging tangled as the tide went out. Do not assume there is enough depth for your boat when rafting up.
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