Student
Carlos Bazan
Santiago, Metropolitana de Santiago, Chile
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Skipper Level I
Status: Sailor
Qualified days: 11
Last exercise doubt.
Posted 2018, Jul 29 00:58
In the last exercise it's said that the true heading is 47º.
According to the last deviation table, the 50º compass heading gives us an approximate deviation of 4º.
If we apply M = C + D, we would obtain 54º M.
Now to obtain the true heading, we should subtract the corresponding variation of 14, which would give us 40º T.
Why 47º T?